Thursday, January 7, 2016

1st Lecture of 2nd Semester



Welcome back! Today we jumped right in to introduce our new unit: aqueous solutions. We hit mostly on how to calculate molarity and what composes a solution.

You can use the formula:
M= mol of solute/L of solution
to determine the molarity of a substance (can be used as a conversion factor).

Also the formula:
M1V1=M2V2
comes in handy when you are given molarity and volume of a solution. That way you are able to solve for a single variable in the equation.

You can be given a molarity problem in many different ways:

  1. originally given molarity
  2. # of moles of chloride ions
  3. grams of a substance that needs to be prepared
These are all being used to determine concentration of ions in a solution.
This whole unit elaborates on a majority of what we learned last semester and building upon it little by little, testing our knowledge of past topics as we move through the rest of the year.

This image provides a good visual of the comparison of concentration of a solution and molarity of a solution:



1 comment:

  1. I love your lay out which helps the reader gain a great understanding of this part of the unit!

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